32x^2+40x-672=0

Solution for 32x^2+40x-672=0 equation:

32x^2+40x-672=0

a = 32; b = 40; c = -672;
Δ = b2-4ac
Δ = 402-4·32·(-672)
Δ = 87616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{87616}=296$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-296}{2*32}=\frac{-336}{64}
=-5+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+296}{2*32}=\frac{256}{64}
=4
$